Contests | Virtual Contests | Problems | Submit | Runs Status | Rank List | Forum |

Time Limit: 0.5 Seconds Memory Limit: 65536K

Total Runs: 1308 Accepted Runs: 659

The expression N!, read as "N factorial," denotes the product of the
first N positive integers, where N is nonnegative. So, for example,

` N N!`
` 0 1`
` 1 1`
` 2 2`
` 3 6`
` 4 24`
` 5 120`
`10 3628800`

For this problem, you are to write a program that can compute the last non-zero digit of any factorial for (0 ≤ N ≤ 10000). For example, if your program is asked to compute the last nonzero digit of 5!, your program should produce "2" because 5! = 120, and 2 is the last nonzero digit of 120.

**Input Format**

Input to the program is a series of nonnegative integers not exceeding 10000, each on its own line with no other letters, digits or spaces. For each integer N, you should read the value and compute the last nonzero digit of N!.

**Required Output Format**

For each integer input, the program should print exactly one line of
output. Each line of output should contain the value N, right-justified
in columns 1 through 5 with leading blanks, not leading zeroes. Columns
6 - 9 must contain "` -> `" (space hyphen greater space). Column 10 must
contain the single last non-zero digit of N!.

**Sample Input**

1 2 26 125 3125 9999

**Sample Output**

1 -> 1 2 -> 2 26 -> 4 125 -> 8 3125 -> 2 9999 -> 8

Maintance:Fxz. Developer: SuperHacker, G.D.Retop, Fxz